Impossible is nothing  
  爱过知情重醉过知酒浓   花开花谢终是空   缘份不停留像春风来又走   女人如花花似梦
公告
日历
<2024年3月>
252627282912
3456789
10111213141516
17181920212223
24252627282930
31123456
统计
  • 随笔 - 8
  • 文章 - 91
  • 评论 - 16
  • 引用 - 0

导航

常用链接

留言簿(4)

随笔分类(4)

随笔档案(8)

文章分类(77)

文章档案(91)

相册

搜索

  •  

最新评论

阅读排行榜

评论排行榜

 
1 下面程序有什么错误:
class base{
private: int i;
public: base(int x){i=x;}
};
class derived: public base{
private: int i;
public: derived(int x, int y) {i=x;}
void printTotal() {int total = i+base::i;}
};



2. Assume you have a class like

class erp
{
HR* m_hr;
FI* m_fi;
public:
erp()
{
m_hr = new HR();
m_fi = new FI();
}
~erp()
{
}
};

if "new FI()" failed in the constructor, how can you detect this problem and
release the properly allocated member pointer m_hr?

3. Check the class and variable definition below:

#include <iostream>
#include <complex>
using namespace std;
class Base
{
public:
Base() { cout<<"Base-ctor"<<endl; }
~Base() { cout<<"Base-dtor"<<endl; }
virtual void f(int) { cout<<"Base::f(int)"<<endl; }
virtual void f(double) {cout<<"Base::f(double)"<<endl; }
virtual void g(int i = 10) {cout<<"Base::g()"<<i<<endl; }
};

class Derived: public Base
{
public:
Derived() { cout<<"Derived-ctor"<<endl; }
~Derived() { cout<<"Derived-dtor"<<endl; }
void f(complex<double>) { cout<<"Derived::f(complex)"<<endl; }
virtual void g(int i = 20) {cout<<"Derived::g()"<<i<<endl; }
};

Base b;
Derived d;

Base* pb = new Derived;
Select the correct one from the four choices:
Cout<<sizeof(Base)<<endl;
A. 4 B.32 C.20 D.Platform-dependent
Cout<<sizeof(Base)<<endl;
A. 4 B.8 C.36 D.Platform-dependent
pb->f(1.0);
A.Derived::f(complex) B.Base::f(double)
pb->g();
A.Base::g() 10 B.Base::g() 20
C.Derived::g() 10 D.Derived::g() 20

4.Implement the simplest singleton pattern(initialize if necessary).

5.Name three sort algorithms you are familiar with. Write out the correct
order by the average time complexity.

6.Write code to sort a duplex direction linklist. The node T has overridden
the comparision operators.


7.Below is usual way we find one element in an array:

const int *find1(const int* array, int n, int x)
{
const int* p = array;
for(int i = 0; i < n; i++)
{
if(*p == x)
{
return p;
}
++p;
}
return 0;
}

In this case we have to bear the knowledge of value type "int", the size of
array, even the existence of an array. Would you re-write it using template
to eliminate all these dependencies?
posted on 2006-04-12 22:35 笑笑生 阅读(1356) 评论(2)  编辑 收藏 引用 所属分类: STL/BOOST
评论:
  • # re: sap的几道笔试题目(转)  任我行 Posted @ 2006-04-13 08:47
    1.
    public: derived(int x, int y) {i=x;}
    //derived(int x, int y):base(y){i=x;}
    void printTotal() {int total = i+#base::i#;}
    2.
    try{
    m_fi = new FI();
    }
    catch(bad_alloc &){
    delete m_hr;
    }

    3.前两题题目重复吧。
    Cout<<sizeof(Base)<<endl; //32
    A. 4 B.32 C.20 D.Platform-dependent
    Cout<<sizeof(Base)<<endl;
    A. 4 B.8 C.36 D.Platform-dependent
    3.3
    pb->f(1.0); //Base::f(double)
    pb->g();//Derived::g()20  回复  更多评论   

  • # re: sap的几道笔试题目(转)  tuesday Posted @ 2006-04-13 19:39
    第二题可以这样做
    template<class T>
    class PWrap
    {
    T* ptr;
    PWrap() { ptr = new T;}
    ~PWrap() {delete ptr;}
    };

    class erp
    {
    PWrap<HR> m_hr;
    PWrap<FI> m_fi;
    };  回复  更多评论   


只有注册用户登录后才能发表评论。
网站导航: 博客园   IT新闻   BlogJava   知识库   博问   管理


 
Copyright © 笑笑生 Powered by: 博客园 模板提供:沪江博客