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POJ 3268

求从原点到达某个点之后返回,来回最长的距离是多少? 比较基础的问题,两遍Dijkstra就可以了。

   1:   
   2:  #include <iostream> 
   3:  #include <vector>
   4:  #include <algorithm>
   5:  #include <queue>
   6:  #include <string.h>
   7:  #include <stdio.h>
   8:  using namespace std;
   9:   
  10:  #define V   1005
  11:  #define E   100005
  12:  #define INF 329999         
  13:   
  14:  // v :the end point of an edge. w : the weight of the weight next:cluster according to the begin point of the edge
  15:  struct node
  16:  {
  17:      int v, w,next;
  18:      node(int vv=0, int ww=0):v(vv),w(ww){}
  19:      bool operator < (const node& r) const{return w> r.w;}
  20:  }pnt[E],pnt1[E];
  21:   
  22:  int e=0,N,M,s;
  23:   
  24:  int head[V];
  25:  int dis[V];
  26:  bool vis[V];
  27:  int src, sink;
  28:   
  29:  void Dijkstra()
  30:  { 
  31:      priority_queue<node> Q; 
  32:      vis[src] = 1; dis[src] = 0; 
  33:      Q.push(node(src, 0)); 
  34:      for (int u = src, i=1; i< N; i++)                 
  35:      { 
  36:          for (int j = head[u]; j != -1; j = pnt[j].next)    // j is edge number.
  37:          { 
  38:              int v = pnt[j].v;                          
  39:              if (vis[v] == 0 && dis[v] > dis[u] + pnt[j].w )// pre is the current vertex
  40:              { 
  41:                  dis[v] = dis[u] + pnt[j].w; 
  42:                  Q.push(node(v, dis[v]));
  43:              } 
  44:          } 
  45:          while (!Q.empty() && vis[Q.top().v]) Q.pop(); 
  46:          if (Q.empty()) break;
  47:          vis[u = Q.top().v] = 1; Q.pop();
  48:      }
  49:  } 
  50:  int head1[V];
  51:  inline void addedge1(int u, int v, int w)
  52:  {
  53:      pnt1[s].v =v; pnt1[s].w = w; pnt1[s].next = head1[u]; head1[u]=s++;
  54:  }
  55:  inline void addedge(int u, int v, int w){ 
  56:      pnt[e].v = v; pnt[e].w = w; pnt[e].next= head[u]; head[u]=e++;
  57:  } 
  58:   
  59:  void Dijkstra_init()
  60:  { 
  61:      e = 0; s =0;
  62:      memset(head, -1, sizeof(head)); 
  63:      memset(head1, -1, sizeof(head));
  64:      memset(vis, 0, sizeof(vis));
  65:      scanf("%d%d", &N , &M);
  66:      for (int i = 0; i <=N; i++) dis[i] = INF; 
  67:      scanf("%d", &src);
  68:      //cout<<src<<endl;
  69:      for(int i=0; i<M; i++)
  70:      {
  71:          int a, b, c;
  72:          scanf("%d%d%d", &a, &b, &c);
  73:          addedge(a, b, c);
  74:          addedge1(b,a, c);
  75:      }
  76:   
  77:   
  78:  } 
  79:   
  80:  int main()
  81:  {
  82:      //freopen("3268.txt","r",stdin);
  83:   
  84:      Dijkstra_init();
  85:      Dijkstra();
  86:      int dis1[V];
  87:      for(int i=0; i<=N; i++) dis1[i] = dis[i];
  88:      //for(int i=1; i<=N; i++) cout<<dis[i]<<" "; cout<<endl;
  89:      memset(vis, 0 ,sizeof(vis));
  90:      for(int i=0; i<=N; i++) { dis[i]= INF; head[i] = head1[i];}
  91:      for(int i=0; i<M; i++)
  92:      {
  93:          pnt[i]=pnt1[i];
  94:   
  95:      }
  96:      Dijkstra();
  97:      //for(int i=1; i<=N; i++) cout<<dis[i]<<" "; cout<<endl;
  98:      int ret = 0;
  99:      for(int i=1; i<=N; i++) ret = max(ret, dis1[i]+dis[i]);
 100:      cout<<ret<<endl;
 101:      return 0;
 102:  }
 103:   

posted on 2012-11-10 00:03 Sosi 阅读(422) 评论(0)  编辑 收藏 引用 所属分类: Algorithm


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