而##可以说是个符号粘合剂。（Modern C++中用来做编译时期内存检查--2.1节 就是用了这个符号）#的用法
The number-sign or "stringizing" operator (#) converts macro parameters (after expansion) to string constants. It is used only with macros that take arguments. If it precedes a formal parameter in the macro definition, the actual argument passed by the macro invocation is enclosed in quotation marks and treated as a string literal. The string literal then replaces each occurrence of a combination of the stringizing operator and formal parameter within the macro definition.
White space preceding the first token of the actual argument and following the last token of the actual argument is ignored. Any white space between the tokens in the actual argument is reduced to a single white space in the resulting string literal. Thus, if a comment occurs between two tokens in the actual argument, it is reduced to a single white space. The resulting string literal is automatically concatenated with any adjacent string literals from which it is separated only by white space.
Further, if a character contained in the argument usually requires an escape sequence when used in a string literal (for example, the quotation mark (") or backslash (\) character), the necessary escape backslash is automatically inserted before the character. The following example shows a macro definition that includes the stringizing operator and a main function that invokes the macro:
#define stringer( x ) printf( #x "\n" )
stringer( In quotes in the printf function call\n );
stringer( "In quotes when printed to the screen"\n );
stringer( "This: \" prints an escaped double quote" );
Such invocations would be expanded during preprocessing, producing the following code:
printf( "In quotes in the printf function call\n" "\n" );
printf( "\"In quotes when printed to the screen\"\n" "\n" );
printf( "\"This: \\\" prints an escaped double quote\"" "\n" );
When the program is run, screen output for each line is as follows:
In quotes in the printf function call
"In quotes when printed to the screen"
"This: \" prints an escaped double quotation mark"
The Microsoft C (versions 6.0 and earlier) extension to the ANSI C standard that previously expanded macro formal arguments appearing inside string literals and character constants is no longer supported. Code that relied on this extension should be rewritten using the stringizing (#) operator.
END Microsoft Specific
The charizing operator can be used only with arguments of macros. If #@ precedes a formal parameter in the definition of the macro, the actual argument is enclosed in single quotation marks and treated as a character when the macro is expanded. For example:
#define makechar(x) #@x
causes the statement
a = makechar(b);
to be expanded to
a = 'b';
The single-quotation character cannot be used with the charizing operator.
END Microsoft Specific
The double-number-sign or "token-pasting" operator (##), which is sometimes called the "merging" operator, is used in both object-like and function-like macros. It permits separate tokens to be joined into a single token and therefore cannot be the first or last token in the macro definition.
If a formal parameter in a macro definition is preceded or followed by the token-pasting operator, the formal parameter is immediately replaced by the unexpanded actual argument. Macro expansion is not performed on the argument prior to replacement.
Then, each occurrence of the token-pasting operator in token-string is removed, and the tokens preceding and following it are concatenated. The resulting token must be a valid token. If it is, the token is scanned for possible replacement if it represents a macro name. The identifier represents the name by which the concatenated tokens will be known in the program before replacement. Each token represents a token defined elsewhere, either within the program or on the compiler command line. White space preceding or following the operator is optional.
This example illustrates use of both the stringizing and token-pasting operators in specifying program output:
#define paster( n ) printf( "token" #n " = %d", token##n )
int token9 = 9;
If a macro is called with a numeric argument like
paster( 9 );
the macro yields
printf( "token" "9" " = %d", token9 );
printf( "token9 = %d", token9 );
posted on 2007-01-19 14:03 CPP&&设计模式小屋
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