Posted on 2011-09-24 22:14
polly 阅读(228)
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模式识别&图像处理
1
#include <stdio.h>
2#include <math.h>
3#include <stdlib.h>
4
/**//*
5
0.500000 1.100000 3.100000
60.000000 -10.040000 -24.500000
70.000000 0.000000 -12.284024
8-2.600000
91.000000
102.000000
11请按任意键继续. . .
12
*/
13#define n 3
14double a[3][3]=
{{0.5,1.1,3.1},{5,0.96,6.5},{2,4.5,0.36}};
15double b[3]={6,0.96,0.02};
16double m[3][3];
17double x[3]={0,0,0};
18int k,p;
19
20int main(){
21
for(k=0;k<n-1;k++){
22 if(a[k][k]==0) break;
23 else{
24 for(int i=k+1;i<n;i++){
25 m[i][k]=a[i][k]/a[k][k];
26 for(int j=k;j<n;j++){
27 a[i][j]=a[i][j]-m[i][k]*a[k][j];
28
}
29 b[i]=b[i]-b[k]*m[i][k];
30 }
31 }
32 }
33 for(int i=0;i<n;i++){
34 for(int j=0;j<3;j++){
35 printf("%f ",a[i][j]);}
36 printf("\n");
37 }
38 //huidai--有错
39 x[n-1]=b[n-1];//Right..
40 for(int i=n-1;i>=0;i--){//where is the error
41 double sum=0;//ok.Vectory.
42 for(int j=i+1;j<n;j++){//Be careful while using for loop!!!
43 sum+=a[i][j]*x[j];
44 }
45 x[i]=(b[i]-sum)/a[i][i];
46 }
47
48 for(int i=0;i<n;i++){
49 printf("%3.2f\n",x[i]);
50 }
51
52 system("pause");
53}
54