HDU 1097 A hard puzzle - Vontroy

//找规律，每4个数循环一次

#include <iostream>

#include <cstdio>

using namespace std;

int main()

{

long long a, b;

int ans[5];

while(cin >> a >> b)

{

if( b == 0 )

{

cout << "1" << endl;

continue;

}

else if( a == 0 )

{

cout << "0" << endl;

continue;

}

ans[1] = a % 10;

ans[2] = (ans[1] * a ) % 10;

ans[3] = (ans[2] * a ) % 10;

ans[4] = (ans[3] * a ) % 10;

int tmp = b % 4;

if( tmp == 0 ) tmp = 4;

cout << ans[tmp] << endl;

}

return 0;

}

posted on 2010-10-03 00:39 Vontroy 阅读(349) 评论(0) 编辑收藏引用所属分类: 数学题、HDU

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