POJ 1005 I Think I Need a Houseboat

/******************************************

设需要n年

设半圆面积为 S，半径为 r

S = 50 * n;

S = (PI * r * r) / 2;

解得 n = (PI * r * r ) / 100;

所给点到原点距离 len = sqrt( x * x + y * y );

令len = r即可解出 n

*******************************************/

#include <iostream>

#include <cstdio>

#include <cmath>

const double PI = 3.1415927;

using namespace std;

int main()

{

double x, y;

int cnt;

cin >> cnt;

int pro = 1;

while( cnt-- )

{

cin >> x >> y;

double len = sqrt( x * x + y * y );

int n = (PI * len * len ) / (100 * 1.0);

printf("Property %d: This property will begin eroding in year %d.\n", pro++, n + 1);

}

cout << "END OF OUTPUT.\n";

return 0;

}

posted on 2010-10-02 19:57 Vontroy 阅读(354) 评论(0) 编辑收藏引用所属分类: 数学题、POJ

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