mod( % ) - wyiu - C++博客

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(a + b)mod c = (a mod c + b mod c) mod c
(a + b)%c = (a % c + b % c) % c
mod相当于除法，效率低

posted on 2009-04-04 19:52 wyiu 阅读(154) 评论(0) 编辑收藏引用

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