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http://poj.org/problem?id=1141
DP, 记录路径。
# include <stdio.h>
# include 
<string.h>

# define N 
205
# define INF 
1000000000
# define Mid (
1 << 10)
# define Lft (
1 << 9 )
# define Rgt (
1 << 8 )

char buf[N];
int f[N][N], p[N][N];

int dp(int x, int y)
{
                
int & ans = f[x][y];
                
if (ans != -1return ans;
                
if (x > y) return ans = 0;
                ans 
= INF;
                
if ( (buf[x]=='('&&buf[y]==')'||
                     (buf[x]
=='['&&buf[y]==']') )
                {
                                
if (ans > dp(x+1, y-1))
                                {
                                                p[x][y] 
= Mid;
                                                ans 
= f[x+1][y-1];
                                }
                }
                
if ( buf[x]=='(' || buf[x]=='[' )
                {
                                
if (ans > dp(x+1, y)+1)
                                {
                                                p[x][y] 
= Rgt;
                                                ans 
= f[x+1][y] + 1;
                                }
                }
                
if ( buf[y]==')' || buf[y]==']' )
                {
                                
if (ans > dp(x, y-1)+1)
                                {
                                                p[x][y] 
= Lft;
                                                ans 
= f[x][y-1+ 1;
                                }
                }
                
for (int i = x; i < y; ++i)
                {
                                
if (ans > dp(x, i)+dp(i+1, y))
                                {
                                                p[x][y] 
= i;
                                                ans 
= f[x][i] + f[i+1][y];
                                }
                }
                
return ans;
}

void print(int s, int t)
{
                
switch(p[s][t])
                {
                                
case Mid:
                                {
                                                putchar(buf[s]), print(s
+1, t-1), putchar(buf[t]);
                                                
break;
                                }
                                
case Lft:
                                {
                                                
if (buf[t] == ')')
                                                                putchar(
'('), print(s, t-1), putchar(')');
                                                
else
                                                                putchar(
'['), print(s, t-1), putchar(']');
                                                
break;
                                }
                                
case Rgt:
                                {
                                                
if (buf[s] == '(')
                                                                putchar(
'('), print(s+1, t), putchar(')');
                                                
else
                                                                putchar(
'['), print(s+1, t), putchar(']');
                                                
break;
                                }
                                
case 0:
                                {
                                                
for (int i = s; i <= t; ++i)
                                                                putchar(buf[i]);
                                                
break;
                                }
                                
default:
                                {
                                                print(s, p[s][t]), print(p[s][t]
+1, t);
                                                
break;
                                }
                }
}

int main()
{
                
int n;

                buf[
0= 0, scanf("%s", buf+1);
                memset(f, 
-1sizeof(f));
                memset(p, 
0sizeof(p));
                n 
= strlen(buf+1);
                dp(
1, n), print(1, n), putchar('\n');

                
return 0;
}

posted on 2012-10-11 13:57 yajunw 阅读(232) 评论(0)  编辑 收藏 引用

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