﻿<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:trackback="http://madskills.com/public/xml/rss/module/trackback/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/"><channel><title>C++博客-yuanyuelang-文章分类-数据结构</title><link>http://www.cppblog.com/yuanyuelang/category/11781.html</link><description /><language>zh-cn</language><lastBuildDate>Sun, 13 Sep 2009 15:38:57 GMT</lastBuildDate><pubDate>Sun, 13 Sep 2009 15:38:57 GMT</pubDate><ttl>60</ttl><item><title>不相交集合数据结构</title><link>http://www.cppblog.com/yuanyuelang/articles/96063.html</link><dc:creator>原语饿狼</dc:creator><author>原语饿狼</author><pubDate>Sun, 13 Sep 2009 12:48:00 GMT</pubDate><guid>http://www.cppblog.com/yuanyuelang/articles/96063.html</guid><wfw:comment>http://www.cppblog.com/yuanyuelang/comments/96063.html</wfw:comment><comments>http://www.cppblog.com/yuanyuelang/articles/96063.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.cppblog.com/yuanyuelang/comments/commentRss/96063.html</wfw:commentRss><trackback:ping>http://www.cppblog.com/yuanyuelang/services/trackbacks/96063.html</trackback:ping><description><![CDATA[<p style="FONT-FAMILY: 隶书; FONT-SIZE: 18pt">不相交集合数据结构保持一组不相交的动态集合s={s1,s2,...}，每个集合通过一个代表来识别，代表是集合中的某个元素。<br><br>不相交集合的应用较为经典的是判断会不会构成连通图，用于最小生成树的Kruskal算法。<br><br>基本操作有：<br>make_set(x):建立一个新的集合，其唯一成员也就是代表为X。代表X都不同，起初各个集合肯定是不相交的。<br><br>union(x,y):将包含x,y元素的集合合并为一个新的集合，此时要选出一个新的代表来代表这个集合，并且将原先的包含x,y元素的集合删除掉，将新集合加入到S中<br><br>find_set(x):返回包含x元素的集合的那个代表。<br><br>综上所述，如何来选择新集合的代表和find_set(x)将是我们要考虑到周密的问题。<br><br>接下来我们介绍按秩合并和路径压缩启发式的方法来解决这个问题<br><br>看代码分析吧：</p>
<div style="BORDER-BOTTOM: #cccccc 1px solid; BORDER-LEFT: #cccccc 1px solid; PADDING-BOTTOM: 4px; BACKGROUND-COLOR: #eeeeee; PADDING-LEFT: 4px; WIDTH: 98%; PADDING-RIGHT: 5px; FONT-SIZE: 13px; WORD-BREAK: break-all; BORDER-TOP: #cccccc 1px solid; BORDER-RIGHT: #cccccc 1px solid; PADDING-TOP: 4px"><span style="COLOR: #0000ff">#define</span><span style="COLOR: #000000">&nbsp;N&nbsp;1000</span><span style="COLOR: #000000"><br></span><span style="COLOR: #0000ff">int</span><span style="COLOR: #000000">&nbsp;p[N],rank[N];<br></span><span style="COLOR: #0000ff">void</span><span style="COLOR: #000000">&nbsp;make_set(</span><span style="COLOR: #0000ff">int</span><span style="COLOR: #000000">&nbsp;x)<br>{<br>&nbsp;&nbsp;p[x]</span><span style="COLOR: #000000">=</span><span style="COLOR: #000000">x;<br>&nbsp;&nbsp;rank[x]</span><span style="COLOR: #000000">=</span><span style="COLOR: #000000">0</span><span style="COLOR: #000000">;<br>}<br><br></span><span style="COLOR: #0000ff">void</span><span style="COLOR: #000000">&nbsp;union(</span><span style="COLOR: #0000ff">int</span><span style="COLOR: #000000">&nbsp;x,</span><span style="COLOR: #0000ff">int</span><span style="COLOR: #000000">&nbsp;y)<br>{<br>&nbsp;&nbsp;</span><span style="COLOR: #0000ff">if</span><span style="COLOR: #000000">(rank[x]</span><span style="COLOR: #000000">&gt;</span><span style="COLOR: #000000">rank[y])<br>&nbsp;&nbsp;&nbsp;&nbsp;p[y]</span><span style="COLOR: #000000">=</span><span style="COLOR: #000000">x;<br>&nbsp;&nbsp;</span><span style="COLOR: #0000ff">else</span><span style="COLOR: #000000">&nbsp;</span><span style="COLOR: #0000ff">if</span><span style="COLOR: #000000">(rank[x]</span><span style="COLOR: #000000">&lt;</span><span style="COLOR: #000000">rank[y])<br>&nbsp;&nbsp;&nbsp;&nbsp;p[x]</span><span style="COLOR: #000000">=</span><span style="COLOR: #000000">y;<br>&nbsp;&nbsp;</span><span style="COLOR: #0000ff">else</span><span style="COLOR: #000000">&nbsp;</span><span style="COLOR: #0000ff">if</span><span style="COLOR: #000000">(rank[x]</span><span style="COLOR: #000000">==</span><span style="COLOR: #000000">rank[y]){<br>&nbsp;&nbsp;&nbsp;&nbsp;p[x]</span><span style="COLOR: #000000">=</span><span style="COLOR: #000000">y;<br>&nbsp;&nbsp;&nbsp;&nbsp;rank[y]</span><span style="COLOR: #000000">++</span><span style="COLOR: #000000">;<br>&nbsp;&nbsp;}<br>}<br><br></span><span style="COLOR: #0000ff">int</span><span style="COLOR: #000000">&nbsp;find_set(</span><span style="COLOR: #0000ff">int</span><span style="COLOR: #000000">&nbsp;x)<br>{<br>&nbsp;</span><span style="COLOR: #0000ff">if</span><span style="COLOR: #000000">(x</span><span style="COLOR: #000000">!=</span><span style="COLOR: #000000">p[x])<br>&nbsp;&nbsp;&nbsp;p[x]</span><span style="COLOR: #000000">=</span><span style="COLOR: #000000">find_set(p[x]);<br>&nbsp;</span><span style="COLOR: #0000ff">return</span><span style="COLOR: #000000">&nbsp;p[x];<br>}<br><br><br></span></div>
<p style="FONT-FAMILY: 隶书; FONT-SIZE: 18pt">建议读者好好几个例子来分析下咯。。。<br><br><br><br><br><br><br><br><br><br><br><br><br><br><br></p>
<img src ="http://www.cppblog.com/yuanyuelang/aggbug/96063.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cppblog.com/yuanyuelang/" target="_blank">原语饿狼</a> 2009-09-13 20:48 <a href="http://www.cppblog.com/yuanyuelang/articles/96063.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item></channel></rss>