C++博客-IT菜鸟-随笔分类-HDOJhttp://www.cppblog.com/micwu/category/16977.html启航zh-cnSun, 26 Jun 2011 17:45:01 GMTSun, 26 Jun 2011 17:45:01 GMT60HUOJ RANK 3713http://www.cppblog.com/micwu/archive/2011/06/22/149156.htmlmicwumicwuWed, 22 Jun 2011 00:33:00 GMThttp://www.cppblog.com/micwu/archive/2011/06/22/149156.htmlhttp://www.cppblog.com/micwu/comments/149156.htmlhttp://www.cppblog.com/micwu/archive/2011/06/22/149156.html#Feedback0http://www.cppblog.com/micwu/comments/commentRss/149156.htmlhttp://www.cppblog.com/micwu/services/trackbacks/149156.htmlmicwu
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micwu 2011-06-22 08:33 发表评论
]]>HUOJ 2089 不要62http://www.cppblog.com/micwu/archive/2011/06/03/147992.htmlmicwumicwuFri, 03 Jun 2011 00:45:00 GMThttp://www.cppblog.com/micwu/archive/2011/06/03/147992.htmlhttp://www.cppblog.com/micwu/comments/147992.htmlhttp://www.cppblog.com/micwu/archive/2011/06/03/147992.html#Feedback0http://www.cppblog.com/micwu/comments/commentRss/147992.htmlhttp://www.cppblog.com/micwu/services/trackbacks/147992.html
判断(4,62)code:


micwu 2011-06-03 08:45 发表评论
]]>HUOJ RANK 4653http://www.cppblog.com/micwu/archive/2011/06/03/147991.htmlmicwumicwuFri, 03 Jun 2011 00:29:00 GMThttp://www.cppblog.com/micwu/archive/2011/06/03/147991.htmlhttp://www.cppblog.com/micwu/comments/147991.htmlhttp://www.cppblog.com/micwu/archive/2011/06/03/147991.html#Feedback0http://www.cppblog.com/micwu/comments/commentRss/147991.htmlhttp://www.cppblog.com/micwu/services/trackbacks/147991.htmlmicwu

registered on 2011-05-18

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micwu 2011-06-03 08:29 发表评论
]]>HDOJ 2058 The sum problemhttp://www.cppblog.com/micwu/archive/2011/05/31/147731.htmlmicwumicwuTue, 31 May 2011 00:19:00 GMThttp://www.cppblog.com/micwu/archive/2011/05/31/147731.htmlhttp://www.cppblog.com/micwu/comments/147731.htmlhttp://www.cppblog.com/micwu/archive/2011/05/31/147731.html#Feedback0http://www.cppblog.com/micwu/comments/commentRss/147731.htmlhttp://www.cppblog.com/micwu/services/trackbacks/147731.html多的不说,2点:
1. 暴力不行,用多项式的和,不然超时是必需的;
    公式: (a+1+a+d)*d/2 = sum =a*d + (d+1)*d/2
2. PE,注意"a blank line".

AC code:


micwu 2011-05-31 08:19 发表评论
]]>HDOJ 2054 A==B?http://www.cppblog.com/micwu/archive/2011/05/30/147673.htmlmicwumicwuMon, 30 May 2011 02:53:00 GMThttp://www.cppblog.com/micwu/archive/2011/05/30/147673.htmlhttp://www.cppblog.com/micwu/comments/147673.htmlhttp://www.cppblog.com/micwu/archive/2011/05/30/147673.html#Feedback0http://www.cppblog.com/micwu/comments/commentRss/147673.htmlhttp://www.cppblog.com/micwu/services/trackbacks/147673.html刚开始就简单的做了2个string的对比,结果...悲
测试数据: 010.000 10
做法:去头0去尾0,去'.'

AC code:



micwu 2011-05-30 10:53 发表评论
]]>HDOJ 2030 汉字统计http://www.cppblog.com/micwu/archive/2011/05/26/147153.htmlmicwumicwuThu, 26 May 2011 00:19:00 GMThttp://www.cppblog.com/micwu/archive/2011/05/26/147153.htmlhttp://www.cppblog.com/micwu/comments/147153.htmlhttp://www.cppblog.com/micwu/archive/2011/05/26/147153.html#Feedback0http://www.cppblog.com/micwu/comments/commentRss/147153.htmlhttp://www.cppblog.com/micwu/services/trackbacks/147153.html
Problem Description
统计给定文本文件中汉字的个数。
Input
输入文件首先包含一个整数n，表示测试实例的个数，然后是n段文本。
Output
对于每一段文本，输出其中的汉字的个数，每个测试实例的输出占一行。

[Hint:]从汉字机内码的特点考虑~
  
汉字编码方式很多，有国标码（GB2312_1980)，大五码，GBK,简体18030，区位码，电报码，还有它们的变形：unicode 大端小端码,UTF-8，UTF-*,HZ 等等。
内码特点 ：二进制双字节，每字节用到8bits.
输入原理,把连续输入的ASCII字符串，通过中文输入软件转化为双字节 中文内码。
输出原理，从 双字节中文内码 查出 字体（font)和 “刻痕",放大/缩小,在频幕或纸上显示打印出来。
解题关键:汉字机内码在计算机的表达方式的描述是，使用二个字节，每个字节最高位一位为1。 
计算机中， 补码第一位是符号位， 1 表示为 负数， 所以 汉字机内码的每个字节表示的十进制数都是负数


micwu 2011-05-26 08:19 发表评论
]]>HDOJ Rank 6777http://www.cppblog.com/micwu/archive/2011/05/26/147152.htmlmicwumicwuThu, 26 May 2011 00:07:00 GMThttp://www.cppblog.com/micwu/archive/2011/05/26/147152.htmlhttp://www.cppblog.com/micwu/comments/147152.htmlhttp://www.cppblog.com/micwu/archive/2011/05/26/147152.html#Feedback0http://www.cppblog.com/micwu/comments/commentRss/147152.htmlhttp://www.cppblog.com/micwu/services/trackbacks/147152.html

micwu

  registered on 2011-05-18

Nationality
Rank 6777
Problems Submitted 42
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Submissions 101
Accepted 52

Last submissions
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micwu 2011-05-26 08:07 发表评论
]]>