C++博客-幽幽-文章分类-HDOJ日志

hdoj1002

幽幽 — Tue, 12 Feb 2008 07:38:00 GMT

A + B Problem II
计算两个1000位以内整数的和
输入
2
1 2
112233445566778899 998877665544332211

输出
Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

#include <iostream>
using namespace std;

int main()
{
    int T, count_T;
    char a[1001], b[1001], ans[1002];
    cin >> T;
    for(count_T=1; count_T <= T; count_T++) {
        cin >> a >> b;
        if(count_T==1) {
            cout << "Case " << count_T << ":" << endl;
        }
        else {
            cout << "\nCase " << count_T << ":" << endl;
        }
        cout << a << " + " << b << " = ";
        int la=strlen(a)-1, lb=strlen(b)-1, sign=0, i;
        for(i=0;la>=0 && lb>=0; la--,lb--,i++) {
            sign += a[la] + b[lb] - '0' - '0';
            ans[i] = sign % 10;
            sign /= 10;
        }
        for(; la>=0; la--, i++) {
            sign += a[la] - '0';
            ans[i] = sign % 10;
            sign /= 10;
        }
        for(; lb>=0; lb--, i++) {
            sign += b[lb] - '0';
            ans[i] = sign % 10;
            sign /= 10;
        }
        if(sign) {
            ans[i] = sign;
            i++;
        }
        for(i--; i>=0; i--) {
            cout << (char)(ans[i] + '0');
        }
        cout << endl;
    }
    return(0);
}

幽幽 2008-02-12 15:38 发表评论

hdoj1001

幽幽 — Tue, 12 Feb 2008 07:36:00 GMT

Sum problem
计算1+2+3+...+n

#include<iostream>
using namespace std;
int main()
{
    int n, temp, sum;
    for(;cin>>n;){
        sum=0;
        for(temp=1; temp<=n; temp++)
            sum+=temp;
        cout << sum << endl << endl;
    }
    return(0);
}

幽幽 2008-02-12 15:36 发表评论

hdoj1000

幽幽 — Tue, 05 Feb 2008 12:37:00 GMT

Problem Description
Calculate A + B.

计算A+B，输入数据有多组，AC的关键是使用C++的输入错误流。

1#include <iostream>
2 using namespace std;
3int main()
4{
5    int a, b;
6    while( cin>>a>>b ) {
7        cout << a+b << endl;
8    }
9    return(0);
10}
11

幽幽 2008-02-05 20:37 发表评论