﻿<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:trackback="http://madskills.com/public/xml/rss/module/trackback/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/"><channel><title>C++博客-Lemon的空间-最新评论</title><link>http://www.cppblog.com/jiyuan/CommentsRSS.aspx</link><description /><language>zh-cn</language><pubDate>Wed, 27 Jan 2010 14:04:02 GMT</pubDate><lastBuildDate>Wed, 27 Jan 2010 14:04:02 GMT</lastBuildDate><generator>cnblogs</generator><item><title>re: pell方程解法--学习笔记</title><link>http://www.cppblog.com/jiyuan/archive/2009/10/07/78543.html#98002</link><dc:creator>lys</dc:creator><author>lys</author><pubDate>Wed, 07 Oct 2009 02:15:00 GMT</pubDate><guid>http://www.cppblog.com/jiyuan/archive/2009/10/07/78543.html#98002</guid><description><![CDATA[这个方程 X2 - D * Y2 = A  怎么求的最小解 （a，b）？ 我的qq 532270685  能告诉我这个算法吗 ？谢谢<img src ="http://www.cppblog.com/jiyuan/aggbug/98002.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cppblog.com/jiyuan/" target="_blank">lys</a> 2009-10-07 10:15 <a href="http://www.cppblog.com/jiyuan/archive/2009/10/07/78543.html#98002#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item></channel></rss>