c++ RTTI中typeid使用

freejohn — Fri, 13 Jul 2012 08:23:00 GMT

1 #include <iostream>
2 #include <string.h>
3 #include <typeinfo.h>
4 using std::cout;
5 using std::endl;
6
7 class graphicimage
8 {
9 protected:
10     char name[80];
11 public:
12     graphicimage()
13     {
14         strcpy(name, "graphicimage");
15     }
16
17     virtual void display()
18     {
19         cout << "display a generic image." << endl;
20     }
21
22     char* getName()
23     {
24         return name;
25     }
26 };
27
28 class GIFImage : public graphicimage
29 {
30 public:
31     GIFImage()
32     {
33         strcpy(name, "GIFImage");
34     }
35
36     void display()
37     {
38         cout << "display a GIF image." << endl;
39     }
40 };
41
42 class PICIamge : public graphicimage
43 {
44 public:
45     PICIamge()
46     {
47         strcpy(name, "PICImage");
48     }
49     void display()
50     {
51         cout << "display a PIC image." << endl;
52     }
53 };
54
55 void process(graphicimage* type)
56 {
57     if(typeid(GIFImage) == typeid(*type))
58     {
59         ((GIFImage*)type)->display();
60     }
61     else if(typeid(PICIamge) == typeid(*type))
62     {
63         ((PICIamge*)type)->display();
64     }
65     else
66     {
67         cout << "Unknow type! " << (typeid(*type)).name() << endl;
68     }
69 }
70
71 int main()
72 {
73     graphicimage *gImage = new GIFImage;
74     graphicimage *pImage = new PICIamge;
75     graphicimage *uImage = new graphicimage;
76
77     process(gImage);
78     process(pImage);
79     process(uImage);
80     system("pause");
81     return 0;
82 }
83

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c++ RTTI中typeid使用