C++博客-C语言学习交流-随笔分类-疑难作业习题解答

谭浩强C习题答案

我爱C — Sun, 07 May 2006 16:54:00 GMT

摘要: 注：这是老版的答案，基本和现在的版本相同，章节标号不同，因为以前没有现在的第二章的内容第一章1.6main(){int a,b,c,max; printf("input three numbers:\n"); scanf("%d,%d,%d",&a,&b,&c); max=a; if(max阅读全文

我爱C 2006-05-08 00:54 发表评论

循环控制上机习题参考答案

我爱C — Thu, 27 Apr 2006 02:40:00 GMT

7.4
main()
{int a[11]={1,4,6,9,13,16,19,28,40,100};
int temp1,temp2,number, end,i,j;
scanf("%d",&number);
end=a[9];
if(number>end) a[10]=number;
else
   {for(i=0;i<10;i++)
      {if(a[i]>number)
        {temp1=a[i];
         a[i]=number;
         for(j=i+1;j<11;j++)
           {temp2=a[j];
            a[j]=temp1;
            temp1=temp2;
           }
         break;
         }
       }
     }
for(i=0;i<11;i++)
   printf("%6d",a[i]);
}

7.5
#define N 5
main()
{int a[N]={8,6,5,4,1},i,temp;
for(i=0;i   {temp=a[i];
    a[i]=a[N-i-1];
    a[N-i-1]=temp;
    }
for(i=0;i   printf("%4d",a[i]);
}

7.8
#define N 10
#define M 10
main()
{int i,j,k,m,n,flag1,flag2,a[N][M],max,maxi,maxj;
scanf("%d,%d",&n,&m);
for(i=0;i   for(j=0;j     scanf("%d",&a[i][j]);
flag2=0;
for(i=0;i   {max=a[i][0];
    for(j=0;j      if(max        {max=a[i][j];
         maxj=j;
        }
    for(k=0,flag1=1;k      if(max>a[k][maxj])flag1=0;
    if(flag1)
      { printf("\na[%d][%d]=%d\n",i,maxj,max);
        flag2=1;
      }
    }
if(!flag2) printf("NOT");
}

7.10
main()
{int i,j,uppn,lown,dign,span,othn;
char text[3][80];
uppn=lown=dign=span=othn=0;
for(i=0;i<3;i++)
   {gets(text[i]);
    for(j=0;j<80&&text[i][j]!='\0';j++)
      {if(text[i][j]>='A'&&text[i][j]<='Z')
         uppn++;
       else if(text[i][j]>='a'&&text[i][j]<='z')
         lown++;
       else if(text[i][j]>='0'&&text[i][j]<='9')
         dign++;
       else if(text[i][j]==' ')
         span++;
       else
         othn++;
       }
    }
for(i=0;i<3;i++)
   printf("%s\n",text[i]);
printf("uppn=%d\n",uppn);
printf("lown=%d\n",lown);
printf("dign=%d\n",dign);
printf("span=%d\n",span);
printf("othn=%d\n",othn);
}

我爱C 2006-04-27 10:40 发表评论

习题解答

我爱C — Mon, 27 Mar 2006 00:51:00 GMT

5.7 给一个不多于5位的正整数，要求：①求他是几位数；②分别打印出每一位数字；③按逆序打印出各位数字。
参考程序：

main()
{   long int num;
     int indiv,ten,hundred,thousand,ten_thousand,palce;/*分别代表个位,十位,百位,千位,万位和位数*/
    printf("please input a integer(0-99999):");
   scanf("%ld",&num);
if(num>9999)
    place=5;
   else if(num>999)
    place=4;
else if(num>99)
   palce=3;
else if(num>9)
   place=2;
else
   place =1;
printf("place=%d\n",place);
ten_thousand=num/10000;
thousand=(num-ten_thousand*10000)/1000;
hundred=(num-ten_thousand*10000-thousand*1000)/100;
ten=(num-ten_thousand*10000-thousand*1000-hundred*100)/10;
indiv=num-ten_thousand*10000-thousand*1000-hundred*100-ten*10;
switch(place)
   {case 5:printf("%d,%d,%d,%d,%d\n",ten_thousand,thousand,hundred,ten,indiv);
           printf("%d,%d,%d,%d,%d\n",indiv,ten,hundred,thousand,ten_thousand);
           break;
    case 4:printf("%d,%d,%d,%d\n",thousand,hundred,ten,indiv);
           printf("%d,%d,%d,%d\n",indiv,ten,hundred,thousand);
           break;
    case 3:printf("%d,%d,%d\n",hundred,ten,indiv);
           printf("%d,%d,%d\n",indiv,ten,hundred);
           break;
    case 2:printf("%d,%d\n",ten,indiv);
           printf("%d,%d\n",indiv,ten);
           break;
    case 1:printf("%d\n",indiv);
           printf("%d\n",indiv);
    }
}

我爱C 2006-03-27 08:51 发表评论