C++博客-SEMAN-文章分类-Code

C++博客-SEMAN-文章分类-Codehttp://www.cppblog.com/SEMAN/category/315.html曾经沧海难为水、除却巫山不是云zh-cnMon, 19 May 2008 18:42:03 GMTMon, 19 May 2008 18:42:03 GMT60将100以内的正整数化为罗马数字http://www.cppblog.com/SEMAN/articles/1049.html味全每日C++味全每日C++Thu, 10 Nov 2005 18:11:00 GMThttp://www.cppblog.com/SEMAN/articles/1049.htmlhttp://www.cppblog.com/SEMAN/comments/1049.htmlhttp://www.cppblog.com/SEMAN/articles/1049.html#Feedback1http://www.cppblog.com/SEMAN/comments/commentRss/1049.htmlhttp://www.cppblog.com/SEMAN/services/trackbacks/1049.html 要求将小于100的整数改写成罗马数字，具体的罗马数字怎么表达的就不详细说了，当时觉得这个题目还是很麻烦的，不过现在想想其中有规律可循的：
1 5 10 50 100 ，我们可以人为地插入 4 9 40 90 这样先求出这几个数的值将大大提高程序的性能

int ator(int n, char *buffer,sizeof(buffer)){
    int GivenNum[9] = {"1","4","5","9","10","40","50","90","100"};
     char Roma[9] ={"I","IV","V","IX","X","XL","L","XC","C"};

     int i = 0;
     while (n>0)
    {
          while (n >= GivenNum[i])
          {
               n = n - GivenNum[i];
               strcat(buff,Roma[i]);
          }
          i = i + 1;
    }
    return 0;
}

受百合上一个兄弟的提醒,突然恍然大悟...哈哈~~

味全每日C++ 2005-11-11 02:11 发表评论

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