﻿<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:trackback="http://madskills.com/public/xml/rss/module/trackback/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/"><channel><title>C++博客-SEMAN-最新评论</title><link>http://www.cppblog.com/SEMAN/CommentsRSS.aspx</link><description>曾经沧海难为水、除却巫山不是云</description><language>zh-cn</language><pubDate>Mon, 04 Sep 2006 06:11:00 GMT</pubDate><lastBuildDate>Mon, 04 Sep 2006 06:11:00 GMT</lastBuildDate><generator>cnblogs</generator><item><title>re: MS的笔试题目</title><link>http://www.cppblog.com/SEMAN/archive/2008/03/07/1118.html#43904</link><dc:creator>521zheng</dc:creator><author>521zheng</author><pubDate>Fri, 07 Mar 2008 09:31:00 GMT</pubDate><guid>http://www.cppblog.com/SEMAN/archive/2008/03/07/1118.html#43904</guid><description><![CDATA[其实没有这么麻烦的，<br>考虑一下二叉查找树的特点，如果两个节点的值都大于或都小于某一个节点的值，就继续遍历下去，否则返回节点的值<br>int FindLowesCommonNode(root * node , int a, int b)<br>{<br>   if(a&lt;=node.value &amp;&amp; b&lt;=node.value)<br>        return FindLowesCommonNode(node-&gt;left, a,b);<br>   if(a&gt;=node.value &amp;&amp; b&gt;=node.value)<br>        return FindLowesCommonNode(node-&gt;right, a,b);<br>   return root.value;  <br>}<img src ="http://www.cppblog.com/SEMAN/aggbug/43904.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cppblog.com/SEMAN/" target="_blank">521zheng</a> 2008-03-07 17:31 <a href="http://www.cppblog.com/SEMAN/archive/2008/03/07/1118.html#43904#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>re: GCC 参数详解</title><link>http://www.cppblog.com/SEMAN/archive/2008/01/01/1440.html#40154</link><dc:creator>秦歌</dc:creator><author>秦歌</author><pubDate>Tue, 01 Jan 2008 05:21:00 GMT</pubDate><guid>http://www.cppblog.com/SEMAN/archive/2008/01/01/1440.html#40154</guid><description><![CDATA[不错的文章！<img src ="http://www.cppblog.com/SEMAN/aggbug/40154.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cppblog.com/SEMAN/" target="_blank">秦歌</a> 2008-01-01 13:21 <a href="http://www.cppblog.com/SEMAN/archive/2008/01/01/1440.html#40154#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>re: My Onepage English Resume[未登录]</title><link>http://www.cppblog.com/SEMAN/archive/2007/08/28/868.html#31041</link><dc:creator>Eric</dc:creator><author>Eric</author><pubDate>Tue, 28 Aug 2007 09:55:00 GMT</pubDate><guid>http://www.cppblog.com/SEMAN/archive/2007/08/28/868.html#31041</guid><description><![CDATA[标准英文简历工作经验时按照倒序，也就是最近的工作经验在前面<img src ="http://www.cppblog.com/SEMAN/aggbug/31041.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cppblog.com/SEMAN/" target="_blank">Eric</a> 2007-08-28 17:55 <a href="http://www.cppblog.com/SEMAN/archive/2007/08/28/868.html#31041#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>re: 二叉树的模板实现</title><link>http://www.cppblog.com/SEMAN/archive/2007/06/13/819.html#26290</link><dc:creator>hello</dc:creator><author>hello</author><pubDate>Wed, 13 Jun 2007 15:58:00 GMT</pubDate><guid>http://www.cppblog.com/SEMAN/archive/2007/06/13/819.html#26290</guid><description><![CDATA[有没有stack.h的头文件亚？<img src ="http://www.cppblog.com/SEMAN/aggbug/26290.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cppblog.com/SEMAN/" target="_blank">hello</a> 2007-06-13 23:58 <a href="http://www.cppblog.com/SEMAN/archive/2007/06/13/819.html#26290#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>re: MS的笔试题目</title><link>http://www.cppblog.com/SEMAN/archive/2006/12/28/1118.html#16964</link><dc:creator>kgha</dc:creator><author>kgha</author><pubDate>Thu, 28 Dec 2006 15:41:00 GMT</pubDate><guid>http://www.cppblog.com/SEMAN/archive/2006/12/28/1118.html#16964</guid><description><![CDATA[这样太费解了，不如写两个函数直观： <br>FindLowestAncestor(Struct TreeNode *pRoot, Struct TreeNode *pNode1, Struct TreeNode *pNode2) <br>{ <br>if (pRoot==NULL) <br>return NULL; <br>if (pRoot==pNode1 &amp;&amp; pRoot==pNode2) <br>return pRoot; <br>Struct TreeNode *pTemp; <br>if (pTemp = FindLowestAncestor(pRoot-&gt;pLeft,pNode1,pNode2)) <br>return pTemp; <br>if (pTemp = FindLowestAncestor(pRoot-&gt;pRight,pNode1,pNode2)) <br>return pTemp; <br>if (FindNode(pRoot,pNode1) &amp;&amp; FindNode(pRoot,pNo <br>de2)) return pRoot; <br>return NULL; <br>} <br>struct TreeNode * FindNode（Struct TreeNode *pRoot, Struct TreeNode *pNode） <br>{ <br>if(pNode在pRoot下) <br>{ <br>return pRoot; <br>} <br>return NULL; <br>} <br>因为最后一步仅仅是在pRoot下是否存在pNode1和pNode2，所以还有优化的余地<br>上面的有点小错误，呵呵<img src ="http://www.cppblog.com/SEMAN/aggbug/16964.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cppblog.com/SEMAN/" target="_blank">kgha</a> 2006-12-28 23:41 <a href="http://www.cppblog.com/SEMAN/archive/2006/12/28/1118.html#16964#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>re: MS的笔试题目</title><link>http://www.cppblog.com/SEMAN/archive/2006/12/28/1118.html#16963</link><dc:creator>kgha</dc:creator><author>kgha</author><pubDate>Thu, 28 Dec 2006 15:37:00 GMT</pubDate><guid>http://www.cppblog.com/SEMAN/archive/2006/12/28/1118.html#16963</guid><description><![CDATA[<br>这样太费解了，不如写两个函数直观：<br>FindLowestAncestor(Struct TreeNode *pRoot, Struct TreeNode *pNode1, Struct TreeNode *pNode2)<br>{<br>   if (pRoot==NULL) <br>      return NULL;<br>   if (pRoot==pNode1 &amp;&amp; pRoot==pNode2) <br>      return pRoot; <br>   Struct TreeNode *pTemp;<br>   if (pTemp = FindLowestAncestor(pRoot-&gt;pLeft,pNode1,pNode2)) <br>      return pTemp;<br>   if (pTemp = FindLowestAncestor(pRoot-&gt;pRight,pNode1,pNode2)) <br>      return pTemp;<br>   if (FindNode(pRoot,pNode1) &amp;&amp; FindLowestAncestor(pRoot,pNo<br>de2)) return pRoot;<br>   return NULL;<br>}<br>struct TreeNode *  FindNode（Struct TreeNode *pRoot, Struct TreeNode *pNode）<br>{<br>    if(pNode在pRoot下)<br>   {<br>       return pRoot;<br>   }<br>    return NULL;<br>}<br>因为最后一步仅仅是在pRoot下是否存在pNode1和pNode2，所以还有优化的余地<img src ="http://www.cppblog.com/SEMAN/aggbug/16963.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cppblog.com/SEMAN/" target="_blank">kgha</a> 2006-12-28 23:37 <a href="http://www.cppblog.com/SEMAN/archive/2006/12/28/1118.html#16963#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>re: MS的笔试题目</title><link>http://www.cppblog.com/SEMAN/archive/2006/12/28/1118.html#16962</link><dc:creator>kgha</dc:creator><author>kgha</author><pubDate>Thu, 28 Dec 2006 15:23:00 GMT</pubDate><guid>http://www.cppblog.com/SEMAN/archive/2006/12/28/1118.html#16962</guid><description><![CDATA[FindLowestAncestor(Struct TreeNode *pRoot, Struct TreeNode *pNode1, Struct TreeNode *pNode2)<br>{<br>   if (pRoot==NULL) <br>      return NULL;<br>   if (pRoot==pNode1 &amp;&amp; pRoot==pNode2) <br>      return pRoot;<br>   Struct TreeNode *pTemp;<br>   if (pTemp = FindLowestAncestor(pRoot-&gt;pLeft,pNode1,pNode2)) <br>      return pTemp;<br>   if (pTemp = FindLowestAncestor(pRoot-&gt;pRight,pNode1,pNode2)) <br>      return pTemp;<br>   if (FindLowestAncestor(pRoot,pNode1,pNode1) &amp;&amp; FindLowestAncestor(pRoot,pNo<br>de2,pNode2)) return pRoot;<br><br>   return NULL;<br>}<br><br><img src ="http://www.cppblog.com/SEMAN/aggbug/16962.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cppblog.com/SEMAN/" target="_blank">kgha</a> 2006-12-28 23:23 <a href="http://www.cppblog.com/SEMAN/archive/2006/12/28/1118.html#16962#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>re: 比饶口令还饶口的复杂声明</title><link>http://www.cppblog.com/SEMAN/archive/2006/12/21/907.html#16677</link><dc:creator>Dain</dc:creator><author>Dain</author><pubDate>Thu, 21 Dec 2006 02:16:00 GMT</pubDate><guid>http://www.cppblog.com/SEMAN/archive/2006/12/21/907.html#16677</guid><description><![CDATA[从右向左读<img src ="http://www.cppblog.com/SEMAN/aggbug/16677.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cppblog.com/SEMAN/" target="_blank">Dain</a> 2006-12-21 10:16 <a href="http://www.cppblog.com/SEMAN/archive/2006/12/21/907.html#16677#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>re: 比饶口令还饶口的复杂声明</title><link>http://www.cppblog.com/SEMAN/archive/2006/12/21/907.html#16675</link><dc:creator>pengkuny</dc:creator><author>pengkuny</author><pubDate>Thu, 21 Dec 2006 01:03:00 GMT</pubDate><guid>http://www.cppblog.com/SEMAN/archive/2006/12/21/907.html#16675</guid><description><![CDATA[不错<img src ="http://www.cppblog.com/SEMAN/aggbug/16675.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cppblog.com/SEMAN/" target="_blank">pengkuny</a> 2006-12-21 09:03 <a href="http://www.cppblog.com/SEMAN/archive/2006/12/21/907.html#16675#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item><item><title>re: MS的笔试题目</title><link>http://www.cppblog.com/SEMAN/archive/2006/10/22/1118.html#14010</link><dc:creator>小小</dc:creator><author>小小</author><pubDate>Sun, 22 Oct 2006 09:18:00 GMT</pubDate><guid>http://www.cppblog.com/SEMAN/archive/2006/10/22/1118.html#14010</guid><description><![CDATA[更多试题，请访问： www.pghome.net/art.html<img src ="http://www.cppblog.com/SEMAN/aggbug/14010.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cppblog.com/SEMAN/" target="_blank">小小</a> 2006-10-22 17:18 <a href="http://www.cppblog.com/SEMAN/archive/2006/10/22/1118.html#14010#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item></channel></rss>