Calculate a+b

Two integer a,b (0<=a,b<=10)

Output a+b

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3

Q: Where are the input and the output?

A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use 'scanf' in C or 'cin' in C++ to read from stdin, and use 'printf' in C or 'cout' in C++ to write to stdout.

You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a "Wrong Answer".

User programs are not allowed to open and read from/write to files. You will get a "Runtime Error" or a "Wrong Answer"if you try to do so.

Here is a sample solution to problem 1000 using C++/G++:

#include <iostream>

using namespace std;

int main()
{
    int a,b;
    cin >> a >> b;
    cout << a+b << endl;
    return 0;
}

It's important that the return type of main() must be int when you use G++/GCC,or you may get compile error.

Here is a sample solution to problem 1000 using C/GCC:

#include <stdio.h>

int main()
{
    int a,b;
    scanf("%d %d",&a, &b);
    printf("%d\n",a+b);
    return 0;
}

Here is a sample solution to problem 1000 using Pascal:

program p1000(Input,Output);

var
  a,b:Integer;
begin
   Readln(a,b);
   Writeln(a+b);
end.

Here is a sample solution to problem 1000 using Java:

Now java compiler is jdk 1.5, next is program for 1000

import java.io.*;
import java.util.*;
public class Main
{
            public static void main(String args[]) throws Exception
            {
                    Scanner cin=new Scanner(System.in);
                    int a=cin.nextInt(),b=cin.nextInt();
                    System.out.println(a+b);
            }
}

Old program for jdk 1.4

import java.io.*;
import java.util.*;

public class Main
{
    public static void main (String args[]) throws Exception
    {
        BufferedReader stdin = 
            new BufferedReader(
                new InputStreamReader(System.in));

        String line = stdin.readLine();
        StringTokenizer st = new StringTokenizer(line);
        int a = Integer.parseInt(st.nextToken());
        int b = Integer.parseInt(st.nextToken());
        System.out.println(a+b);
    }
}

Here is a sample solution to problem 1000 using Fortran:

	PROGRAM P1000
		IMPLICIT NONE
		INTEGER :: A, B
		READ(*,*) A, B
		WRITE(*, "(I0)") A + B
	END PROGRAM P1000

计算a加b。

两个整数a和b，其中0≤a, b≤10。

输出a与b的和。

1 2

3

问：怎样输入输出？
答：你的程序应该从标准输入(stdin)中读取数据，而将结果写到标准输出(stdout)。比如，在C语言中你可以使用“scanf”，在C++语言中则可以使用“cin”来输入；输出可以使用C语言的“printf”或者C++语言的“cout”。其他的语言可以参照下面的程序。

注意：不要向标准输出写入题目要求输出结果之外的其他数据，否则你会被判为“Wrong Answer”，即错误的运行结果。

你的程序也不能试图读或写任何文件，否则你可能被判为“Runtime Error”(运行时错误)或“Wrong Answer”(错误结果)。

下面是这道题的一个C++或者G++的程序。

#include <iostream>
using namespace std;
int main()
{
    int a,b;
    cin >> a >> b;
    cout << a+b << endl;
    return 0;
}

注意：对于GCC或者G++，main()函数的返回值必须是int型，否则可能导致“Compile Error”即编译错误。

下面是这道题的一个C或者GCC的程序。

#include <stdio.h>

int main()
{
    int a,b;
    scanf("%d %d",&a, &b);
    printf("%d\n",a+b);
    return 0;
}

下面是这道题的一个Pascal程序。

program p1000(Input,Output);
var
  a,b:Integer;
begin
   Readln(a,b);
   Writeln(a+b);
end.

下面是这道题的一个Java程序，这里Java编译器采用的是JDK 1.5。

import java.io.*;
import java.util.*;
public class Main
{
            public static void main(String args[]) throws Exception
            {
                    Scanner cin=new Scanner(System.in);
                    int a=cin.nextInt(),b=cin.nextInt();
                    System.out.println(a+b);
            }
}

而老版本的JDK 1.4程序如下：

import java.io.*;
import java.util.*;

public class Main
{
    public static void main (String args[]) throws Exception
    {
        BufferedReader stdin = 
            new BufferedReader(
                new InputStreamReader(System.in));

        String line = stdin.readLine();
        StringTokenizer st = new StringTokenizer(line);
        int a = Integer.parseInt(st.nextToken());
        int b = Integer.parseInt(st.nextToken());
        System.out.println(a+b);
    }
}

下面是这道题的一个Fortran程序。

	PROGRAM P1000
		IMPLICIT NONE
		INTEGER :: A, B
		READ(*,*) A, B
		WRITE(*, "(I0)") A + B
	END PROGRAM P1000

Xie Di, xiedi@POJ