﻿<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:trackback="http://madskills.com/public/xml/rss/module/trackback/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/"><channel><title>C++博客-Mato is No.1-随笔分类-位运算</title><link>http://www.cppblog.com/MatoNo1/category/19330.html</link><description>Mato是一只超级大沙茶……比赛结果从后往前排列，Mato总是No.1……</description><language>zh-cn</language><lastBuildDate>Sun, 20 May 2012 02:34:09 GMT</lastBuildDate><pubDate>Sun, 20 May 2012 02:34:09 GMT</pubDate><ttl>60</ttl><item><title>XOR专题（一）：异或方程组的解法</title><link>http://www.cppblog.com/MatoNo1/archive/2012/05/20/175404.html</link><dc:creator>Mato_No1</dc:creator><author>Mato_No1</author><pubDate>Sun, 20 May 2012 02:17:00 GMT</pubDate><guid>http://www.cppblog.com/MatoNo1/archive/2012/05/20/175404.html</guid><wfw:comment>http://www.cppblog.com/MatoNo1/comments/175404.html</wfw:comment><comments>http://www.cppblog.com/MatoNo1/archive/2012/05/20/175404.html#Feedback</comments><slash:comments>0</slash:comments><wfw:commentRss>http://www.cppblog.com/MatoNo1/comments/commentRss/175404.html</wfw:commentRss><trackback:ping>http://www.cppblog.com/MatoNo1/services/trackbacks/175404.html</trackback:ping><description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 摘要: 【异或（XOR）运算由于与&#8220;奇偶性&#8221;密切相关，经常出现在有关奇偶性和二进制的题目中】很多异或问题都要涉及到解异或方程组，因此首先要搞懂异或方程组的解法。（1）异或方程组的格式（设有n个未知数，m个方程）：a11*x1 XOR a12*x2 XOR ... XOR a1n*xn = b1a21*x1 XOR a22*x2 XOR ... XOR a2n*xn = b2&#82...&nbsp;&nbsp;<a href='http://www.cppblog.com/MatoNo1/archive/2012/05/20/175404.html'>阅读全文</a><img src ="http://www.cppblog.com/MatoNo1/aggbug/175404.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cppblog.com/MatoNo1/" target="_blank">Mato_No1</a> 2012-05-20 10:17 <a href="http://www.cppblog.com/MatoNo1/archive/2012/05/20/175404.html#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item></channel></rss>