一段转换guid字符串的lua代码

Bee — Sun, 25 Oct 2009 04:56:00 GMT

--guid2.lua
--s = "{0xCC3F04F7, 0x3198, 0x407E, {0xA0, 0x05, 0x73, 0xBA, 0xB6, 0xD3, 0xC2, 0x67} }"
s = "CC3F04F7-3198-407E-A005-73BAB6D3C267"
-- 通过flag表来控制将纯32位数字纯转换为什么格式的guid串
function convert_with_flags(s_guid, tblflags)
if string.len(s_guid) ~= 32 or type(tblflags) ~= "table" then
  error "parameter is invalid"
  return
end
local s_ret = ""
local n_elements = table.getn(tblflags)
for i = 1, n_elements, 1 do
  if type(tblflags[i]) == "string" then
   s_ret = s_ret..tblflags[i]
  elseif type(tblflags[i]) == "table" then
   s_ret = s_ret..string.sub(s_guid, tblflags[i][1], tblflags[i][2])
  end
end
return s_ret
end
-- 将guid字符串转换成32位数字串
function make_pure_guid(s)
local s_pure = string.gsub(string.upper(s), "0X", "")
s_pure = string.gsub(s_pure, "%X", "")
return s_pure
end
function convert2cstyle(s)
local s_pure = make_pure_guid(s)
if string.len(s_pure) ~= 32 then
  error "invalid guid string"
  return
end
local tbl_flags = {"{0x", {1, 8}, ", 0x", {9, 12}, ", 0x", { 13, 16},
     ", {0x", {17, 18}, ", 0x", {19, 20}, ", 0x", {21, 22},
     ", 0x", {23, 24}, ", 0x", {25, 26}, ", 0x", {27, 28},
     ", 0x", {29, 30}, ", 0x", {31, 32}, "} }"
    }
return convert_with_flags(s_pure, tbl_flags)
end
function convert2normal(s)
local s_pure = make_pure_guid(s)
if string.len(s_pure) ~= 32 then
  error "invalid guid string"
  return
end
local tbl_flags = {{1, 8}, "-", {9, 12}, "-", { 13, 16},
     "-", {17, 20}, "-", {21, 32}
    }
return convert_with_flags(s_pure, tbl_flags)
end
print("s = "..s)
s_guid_normal = convert2normal(s)
print("s_guid_normal = "..s_guid_normal)
s_guid_cstyle = convert2cstyle(s_guid_normal)
print("s_guid_cstyle = "..s_guid_cstyle)

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一段转换guid字符串的lua代码