﻿<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:trackback="http://madskills.com/public/xml/rss/module/trackback/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/"><channel><title>C++博客-Achilleus Daily-最新评论</title><link>http://www.cppblog.com/Achilleus/CommentsRSS.aspx</link><description /><language>zh-cn</language><pubDate>Thu, 01 Sep 2011 12:27:24 GMT</pubDate><lastBuildDate>Thu, 01 Sep 2011 12:27:24 GMT</lastBuildDate><generator>cnblogs</generator><item><title>re: Lambda算子简介</title><link>http://www.cppblog.com/Achilleus/archive/2016/05/23/154768.html#213569</link><dc:creator>Nicoder</dc:creator><author>Nicoder</author><pubDate>Mon, 23 May 2016 02:32:00 GMT</pubDate><guid>http://www.cppblog.com/Achilleus/archive/2016/05/23/154768.html#213569</guid><description><![CDATA[ 你好，在2.算子这一节中，将后继函数作用于λsz.z时λyx.y((λsz.z)yx) = λyx.y((λz.z)x) 这一步是怎么算出来的?不太懂<img src ="http://www.cppblog.com/Achilleus/aggbug/213569.html" width = "1" height = "1" /><br><br><div align=right><a style="text-decoration:none;" href="http://www.cppblog.com/Achilleus/" target="_blank">Nicoder</a> 2016-05-23 10:32 <a href="http://www.cppblog.com/Achilleus/archive/2016/05/23/154768.html#213569#Feedback" target="_blank" style="text-decoration:none;">发表评论</a></div>]]></description></item></channel></rss>